3.248 \(\int \frac{1}{(e \cot (c+d x))^{7/2} (a+a \sec (c+d x))} \, dx\)

Optimal. Leaf size=335 \[ -\frac{\sqrt{\sin (2 c+2 d x)} \cot ^3(c+d x) \csc (c+d x) \text{EllipticF}\left (c+d x-\frac{\pi }{4},2\right )}{3 a d (e \cot (c+d x))^{7/2}}-\frac{2 \cot ^3(c+d x) (3-\sec (c+d x))}{3 a d (e \cot (c+d x))^{7/2}}-\frac{\tan ^{-1}\left (1-\sqrt{2} \sqrt{\tan (c+d x)}\right )}{\sqrt{2} a d \tan ^{\frac{7}{2}}(c+d x) (e \cot (c+d x))^{7/2}}+\frac{\tan ^{-1}\left (\sqrt{2} \sqrt{\tan (c+d x)}+1\right )}{\sqrt{2} a d \tan ^{\frac{7}{2}}(c+d x) (e \cot (c+d x))^{7/2}}-\frac{\log \left (\tan (c+d x)-\sqrt{2} \sqrt{\tan (c+d x)}+1\right )}{2 \sqrt{2} a d \tan ^{\frac{7}{2}}(c+d x) (e \cot (c+d x))^{7/2}}+\frac{\log \left (\tan (c+d x)+\sqrt{2} \sqrt{\tan (c+d x)}+1\right )}{2 \sqrt{2} a d \tan ^{\frac{7}{2}}(c+d x) (e \cot (c+d x))^{7/2}} \]

[Out]

(-2*Cot[c + d*x]^3*(3 - Sec[c + d*x]))/(3*a*d*(e*Cot[c + d*x])^(7/2)) - (Cot[c + d*x]^3*Csc[c + d*x]*EllipticF
[c - Pi/4 + d*x, 2]*Sqrt[Sin[2*c + 2*d*x]])/(3*a*d*(e*Cot[c + d*x])^(7/2)) - ArcTan[1 - Sqrt[2]*Sqrt[Tan[c + d
*x]]]/(Sqrt[2]*a*d*(e*Cot[c + d*x])^(7/2)*Tan[c + d*x]^(7/2)) + ArcTan[1 + Sqrt[2]*Sqrt[Tan[c + d*x]]]/(Sqrt[2
]*a*d*(e*Cot[c + d*x])^(7/2)*Tan[c + d*x]^(7/2)) - Log[1 - Sqrt[2]*Sqrt[Tan[c + d*x]] + Tan[c + d*x]]/(2*Sqrt[
2]*a*d*(e*Cot[c + d*x])^(7/2)*Tan[c + d*x]^(7/2)) + Log[1 + Sqrt[2]*Sqrt[Tan[c + d*x]] + Tan[c + d*x]]/(2*Sqrt
[2]*a*d*(e*Cot[c + d*x])^(7/2)*Tan[c + d*x]^(7/2))

________________________________________________________________________________________

Rubi [A]  time = 0.337375, antiderivative size = 335, normalized size of antiderivative = 1., number of steps used = 18, number of rules used = 15, integrand size = 25, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.6, Rules used = {3900, 3888, 3881, 3884, 3476, 329, 211, 1165, 628, 1162, 617, 204, 2614, 2573, 2641} \[ -\frac{2 \cot ^3(c+d x) (3-\sec (c+d x))}{3 a d (e \cot (c+d x))^{7/2}}-\frac{\tan ^{-1}\left (1-\sqrt{2} \sqrt{\tan (c+d x)}\right )}{\sqrt{2} a d \tan ^{\frac{7}{2}}(c+d x) (e \cot (c+d x))^{7/2}}+\frac{\tan ^{-1}\left (\sqrt{2} \sqrt{\tan (c+d x)}+1\right )}{\sqrt{2} a d \tan ^{\frac{7}{2}}(c+d x) (e \cot (c+d x))^{7/2}}-\frac{\log \left (\tan (c+d x)-\sqrt{2} \sqrt{\tan (c+d x)}+1\right )}{2 \sqrt{2} a d \tan ^{\frac{7}{2}}(c+d x) (e \cot (c+d x))^{7/2}}+\frac{\log \left (\tan (c+d x)+\sqrt{2} \sqrt{\tan (c+d x)}+1\right )}{2 \sqrt{2} a d \tan ^{\frac{7}{2}}(c+d x) (e \cot (c+d x))^{7/2}}-\frac{\sqrt{\sin (2 c+2 d x)} \cot ^3(c+d x) \csc (c+d x) F\left (\left .c+d x-\frac{\pi }{4}\right |2\right )}{3 a d (e \cot (c+d x))^{7/2}} \]

Antiderivative was successfully verified.

[In]

Int[1/((e*Cot[c + d*x])^(7/2)*(a + a*Sec[c + d*x])),x]

[Out]

(-2*Cot[c + d*x]^3*(3 - Sec[c + d*x]))/(3*a*d*(e*Cot[c + d*x])^(7/2)) - (Cot[c + d*x]^3*Csc[c + d*x]*EllipticF
[c - Pi/4 + d*x, 2]*Sqrt[Sin[2*c + 2*d*x]])/(3*a*d*(e*Cot[c + d*x])^(7/2)) - ArcTan[1 - Sqrt[2]*Sqrt[Tan[c + d
*x]]]/(Sqrt[2]*a*d*(e*Cot[c + d*x])^(7/2)*Tan[c + d*x]^(7/2)) + ArcTan[1 + Sqrt[2]*Sqrt[Tan[c + d*x]]]/(Sqrt[2
]*a*d*(e*Cot[c + d*x])^(7/2)*Tan[c + d*x]^(7/2)) - Log[1 - Sqrt[2]*Sqrt[Tan[c + d*x]] + Tan[c + d*x]]/(2*Sqrt[
2]*a*d*(e*Cot[c + d*x])^(7/2)*Tan[c + d*x]^(7/2)) + Log[1 + Sqrt[2]*Sqrt[Tan[c + d*x]] + Tan[c + d*x]]/(2*Sqrt
[2]*a*d*(e*Cot[c + d*x])^(7/2)*Tan[c + d*x]^(7/2))

Rule 3900

Int[(cot[(c_.) + (d_.)*(x_)]*(e_.))^(m_)*((a_) + (b_.)*sec[(c_.) + (d_.)*(x_)])^(n_.), x_Symbol] :> Dist[(e*Co
t[c + d*x])^m*Tan[c + d*x]^m, Int[(a + b*Sec[c + d*x])^n/Tan[c + d*x]^m, x], x] /; FreeQ[{a, b, c, d, e, m, n}
, x] &&  !IntegerQ[m]

Rule 3888

Int[(cot[(c_.) + (d_.)*(x_)]*(e_.))^(m_)*(csc[(c_.) + (d_.)*(x_)]*(b_.) + (a_))^(n_), x_Symbol] :> Dist[a^(2*n
)/e^(2*n), Int[(e*Cot[c + d*x])^(m + 2*n)/(-a + b*Csc[c + d*x])^n, x], x] /; FreeQ[{a, b, c, d, e, m}, x] && E
qQ[a^2 - b^2, 0] && ILtQ[n, 0]

Rule 3881

Int[(cot[(c_.) + (d_.)*(x_)]*(e_.))^(m_)*(csc[(c_.) + (d_.)*(x_)]*(b_.) + (a_)), x_Symbol] :> -Simp[(e*(e*Cot[
c + d*x])^(m - 1)*(a*m + b*(m - 1)*Csc[c + d*x]))/(d*m*(m - 1)), x] - Dist[e^2/m, Int[(e*Cot[c + d*x])^(m - 2)
*(a*m + b*(m - 1)*Csc[c + d*x]), x], x] /; FreeQ[{a, b, c, d, e}, x] && GtQ[m, 1]

Rule 3884

Int[(cot[(c_.) + (d_.)*(x_)]*(e_.))^(m_.)*(csc[(c_.) + (d_.)*(x_)]*(b_.) + (a_)), x_Symbol] :> Dist[a, Int[(e*
Cot[c + d*x])^m, x], x] + Dist[b, Int[(e*Cot[c + d*x])^m*Csc[c + d*x], x], x] /; FreeQ[{a, b, c, d, e, m}, x]

Rule 3476

Int[((b_.)*tan[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Dist[b/d, Subst[Int[x^n/(b^2 + x^2), x], x, b*Tan[c + d
*x]], x] /; FreeQ[{b, c, d, n}, x] &&  !IntegerQ[n]

Rule 329

Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> With[{k = Denominator[m]}, Dist[k/c, Subst[I
nt[x^(k*(m + 1) - 1)*(a + (b*x^(k*n))/c^n)^p, x], x, (c*x)^(1/k)], x]] /; FreeQ[{a, b, c, p}, x] && IGtQ[n, 0]
&& FractionQ[m] && IntBinomialQ[a, b, c, n, m, p, x]

Rule 211

Int[((a_) + (b_.)*(x_)^4)^(-1), x_Symbol] :> With[{r = Numerator[Rt[a/b, 2]], s = Denominator[Rt[a/b, 2]]}, Di
st[1/(2*r), Int[(r - s*x^2)/(a + b*x^4), x], x] + Dist[1/(2*r), Int[(r + s*x^2)/(a + b*x^4), x], x]] /; FreeQ[
{a, b}, x] && (GtQ[a/b, 0] || (PosQ[a/b] && AtomQ[SplitProduct[SumBaseQ, a]] && AtomQ[SplitProduct[SumBaseQ, b
]]))

Rule 1165

Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[(-2*d)/e, 2]}, Dist[e/(2*c*q), Int[
(q - 2*x)/Simp[d/e + q*x - x^2, x], x], x] + Dist[e/(2*c*q), Int[(q + 2*x)/Simp[d/e - q*x - x^2, x], x], x]] /
; FreeQ[{a, c, d, e}, x] && EqQ[c*d^2 - a*e^2, 0] && NegQ[d*e]

Rule 628

Int[((d_) + (e_.)*(x_))/((a_.) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> Simp[(d*Log[RemoveContent[a + b*x +
c*x^2, x]])/b, x] /; FreeQ[{a, b, c, d, e}, x] && EqQ[2*c*d - b*e, 0]

Rule 1162

Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[(2*d)/e, 2]}, Dist[e/(2*c), Int[1/S
imp[d/e + q*x + x^2, x], x], x] + Dist[e/(2*c), Int[1/Simp[d/e - q*x + x^2, x], x], x]] /; FreeQ[{a, c, d, e},
x] && EqQ[c*d^2 - a*e^2, 0] && PosQ[d*e]

Rule 617

Int[((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> With[{q = 1 - 4*Simplify[(a*c)/b^2]}, Dist[-2/b, Sub
st[Int[1/(q - x^2), x], x, 1 + (2*c*x)/b], x] /; RationalQ[q] && (EqQ[q^2, 1] ||  !RationalQ[b^2 - 4*a*c])] /;
FreeQ[{a, b, c}, x] && NeQ[b^2 - 4*a*c, 0]

Rule 204

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> -Simp[ArcTan[(Rt[-b, 2]*x)/Rt[-a, 2]]/(Rt[-a, 2]*Rt[-b, 2]), x] /
; FreeQ[{a, b}, x] && PosQ[a/b] && (LtQ[a, 0] || LtQ[b, 0])

Rule 2614

Int[sec[(e_.) + (f_.)*(x_)]/Sqrt[(b_.)*tan[(e_.) + (f_.)*(x_)]], x_Symbol] :> Dist[Sqrt[Sin[e + f*x]]/(Sqrt[Co
s[e + f*x]]*Sqrt[b*Tan[e + f*x]]), Int[1/(Sqrt[Cos[e + f*x]]*Sqrt[Sin[e + f*x]]), x], x] /; FreeQ[{b, e, f}, x
]

Rule 2573

Int[1/(Sqrt[cos[(e_.) + (f_.)*(x_)]*(b_.)]*Sqrt[(a_.)*sin[(e_.) + (f_.)*(x_)]]), x_Symbol] :> Dist[Sqrt[Sin[2*
e + 2*f*x]]/(Sqrt[a*Sin[e + f*x]]*Sqrt[b*Cos[e + f*x]]), Int[1/Sqrt[Sin[2*e + 2*f*x]], x], x] /; FreeQ[{a, b,
e, f}, x]

Rule 2641

Int[1/Sqrt[sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[(2*EllipticF[(1*(c - Pi/2 + d*x))/2, 2])/d, x] /; FreeQ
[{c, d}, x]

Rubi steps

\begin{align*} \int \frac{1}{(e \cot (c+d x))^{7/2} (a+a \sec (c+d x))} \, dx &=\frac{\int \frac{\tan ^{\frac{7}{2}}(c+d x)}{a+a \sec (c+d x)} \, dx}{(e \cot (c+d x))^{7/2} \tan ^{\frac{7}{2}}(c+d x)}\\ &=\frac{\int (-a+a \sec (c+d x)) \tan ^{\frac{3}{2}}(c+d x) \, dx}{a^2 (e \cot (c+d x))^{7/2} \tan ^{\frac{7}{2}}(c+d x)}\\ &=-\frac{2 \cot ^3(c+d x) (3-\sec (c+d x))}{3 a d (e \cot (c+d x))^{7/2}}-\frac{2 \int \frac{-\frac{3 a}{2}+\frac{1}{2} a \sec (c+d x)}{\sqrt{\tan (c+d x)}} \, dx}{3 a^2 (e \cot (c+d x))^{7/2} \tan ^{\frac{7}{2}}(c+d x)}\\ &=-\frac{2 \cot ^3(c+d x) (3-\sec (c+d x))}{3 a d (e \cot (c+d x))^{7/2}}-\frac{\int \frac{\sec (c+d x)}{\sqrt{\tan (c+d x)}} \, dx}{3 a (e \cot (c+d x))^{7/2} \tan ^{\frac{7}{2}}(c+d x)}+\frac{\int \frac{1}{\sqrt{\tan (c+d x)}} \, dx}{a (e \cot (c+d x))^{7/2} \tan ^{\frac{7}{2}}(c+d x)}\\ &=-\frac{2 \cot ^3(c+d x) (3-\sec (c+d x))}{3 a d (e \cot (c+d x))^{7/2}}-\frac{\cos ^{\frac{7}{2}}(c+d x) \int \frac{1}{\sqrt{\cos (c+d x)} \sqrt{\sin (c+d x)}} \, dx}{3 a (e \cot (c+d x))^{7/2} \sin ^{\frac{7}{2}}(c+d x)}+\frac{\operatorname{Subst}\left (\int \frac{1}{\sqrt{x} \left (1+x^2\right )} \, dx,x,\tan (c+d x)\right )}{a d (e \cot (c+d x))^{7/2} \tan ^{\frac{7}{2}}(c+d x)}\\ &=-\frac{2 \cot ^3(c+d x) (3-\sec (c+d x))}{3 a d (e \cot (c+d x))^{7/2}}-\frac{\left (\cot ^3(c+d x) \csc (c+d x) \sqrt{\sin (2 c+2 d x)}\right ) \int \frac{1}{\sqrt{\sin (2 c+2 d x)}} \, dx}{3 a (e \cot (c+d x))^{7/2}}+\frac{2 \operatorname{Subst}\left (\int \frac{1}{1+x^4} \, dx,x,\sqrt{\tan (c+d x)}\right )}{a d (e \cot (c+d x))^{7/2} \tan ^{\frac{7}{2}}(c+d x)}\\ &=-\frac{2 \cot ^3(c+d x) (3-\sec (c+d x))}{3 a d (e \cot (c+d x))^{7/2}}-\frac{\cot ^3(c+d x) \csc (c+d x) F\left (\left .c-\frac{\pi }{4}+d x\right |2\right ) \sqrt{\sin (2 c+2 d x)}}{3 a d (e \cot (c+d x))^{7/2}}+\frac{\operatorname{Subst}\left (\int \frac{1-x^2}{1+x^4} \, dx,x,\sqrt{\tan (c+d x)}\right )}{a d (e \cot (c+d x))^{7/2} \tan ^{\frac{7}{2}}(c+d x)}+\frac{\operatorname{Subst}\left (\int \frac{1+x^2}{1+x^4} \, dx,x,\sqrt{\tan (c+d x)}\right )}{a d (e \cot (c+d x))^{7/2} \tan ^{\frac{7}{2}}(c+d x)}\\ &=-\frac{2 \cot ^3(c+d x) (3-\sec (c+d x))}{3 a d (e \cot (c+d x))^{7/2}}-\frac{\cot ^3(c+d x) \csc (c+d x) F\left (\left .c-\frac{\pi }{4}+d x\right |2\right ) \sqrt{\sin (2 c+2 d x)}}{3 a d (e \cot (c+d x))^{7/2}}+\frac{\operatorname{Subst}\left (\int \frac{1}{1-\sqrt{2} x+x^2} \, dx,x,\sqrt{\tan (c+d x)}\right )}{2 a d (e \cot (c+d x))^{7/2} \tan ^{\frac{7}{2}}(c+d x)}+\frac{\operatorname{Subst}\left (\int \frac{1}{1+\sqrt{2} x+x^2} \, dx,x,\sqrt{\tan (c+d x)}\right )}{2 a d (e \cot (c+d x))^{7/2} \tan ^{\frac{7}{2}}(c+d x)}-\frac{\operatorname{Subst}\left (\int \frac{\sqrt{2}+2 x}{-1-\sqrt{2} x-x^2} \, dx,x,\sqrt{\tan (c+d x)}\right )}{2 \sqrt{2} a d (e \cot (c+d x))^{7/2} \tan ^{\frac{7}{2}}(c+d x)}-\frac{\operatorname{Subst}\left (\int \frac{\sqrt{2}-2 x}{-1+\sqrt{2} x-x^2} \, dx,x,\sqrt{\tan (c+d x)}\right )}{2 \sqrt{2} a d (e \cot (c+d x))^{7/2} \tan ^{\frac{7}{2}}(c+d x)}\\ &=-\frac{2 \cot ^3(c+d x) (3-\sec (c+d x))}{3 a d (e \cot (c+d x))^{7/2}}-\frac{\cot ^3(c+d x) \csc (c+d x) F\left (\left .c-\frac{\pi }{4}+d x\right |2\right ) \sqrt{\sin (2 c+2 d x)}}{3 a d (e \cot (c+d x))^{7/2}}-\frac{\log \left (1-\sqrt{2} \sqrt{\tan (c+d x)}+\tan (c+d x)\right )}{2 \sqrt{2} a d (e \cot (c+d x))^{7/2} \tan ^{\frac{7}{2}}(c+d x)}+\frac{\log \left (1+\sqrt{2} \sqrt{\tan (c+d x)}+\tan (c+d x)\right )}{2 \sqrt{2} a d (e \cot (c+d x))^{7/2} \tan ^{\frac{7}{2}}(c+d x)}+\frac{\operatorname{Subst}\left (\int \frac{1}{-1-x^2} \, dx,x,1-\sqrt{2} \sqrt{\tan (c+d x)}\right )}{\sqrt{2} a d (e \cot (c+d x))^{7/2} \tan ^{\frac{7}{2}}(c+d x)}-\frac{\operatorname{Subst}\left (\int \frac{1}{-1-x^2} \, dx,x,1+\sqrt{2} \sqrt{\tan (c+d x)}\right )}{\sqrt{2} a d (e \cot (c+d x))^{7/2} \tan ^{\frac{7}{2}}(c+d x)}\\ &=-\frac{2 \cot ^3(c+d x) (3-\sec (c+d x))}{3 a d (e \cot (c+d x))^{7/2}}-\frac{\cot ^3(c+d x) \csc (c+d x) F\left (\left .c-\frac{\pi }{4}+d x\right |2\right ) \sqrt{\sin (2 c+2 d x)}}{3 a d (e \cot (c+d x))^{7/2}}-\frac{\tan ^{-1}\left (1-\sqrt{2} \sqrt{\tan (c+d x)}\right )}{\sqrt{2} a d (e \cot (c+d x))^{7/2} \tan ^{\frac{7}{2}}(c+d x)}+\frac{\tan ^{-1}\left (1+\sqrt{2} \sqrt{\tan (c+d x)}\right )}{\sqrt{2} a d (e \cot (c+d x))^{7/2} \tan ^{\frac{7}{2}}(c+d x)}-\frac{\log \left (1-\sqrt{2} \sqrt{\tan (c+d x)}+\tan (c+d x)\right )}{2 \sqrt{2} a d (e \cot (c+d x))^{7/2} \tan ^{\frac{7}{2}}(c+d x)}+\frac{\log \left (1+\sqrt{2} \sqrt{\tan (c+d x)}+\tan (c+d x)\right )}{2 \sqrt{2} a d (e \cot (c+d x))^{7/2} \tan ^{\frac{7}{2}}(c+d x)}\\ \end{align*}

Mathematica [C]  time = 15.1426, size = 130, normalized size = 0.39 \[ -\frac{4 \sin ^2\left (\frac{1}{2} (c+d x)\right ) \csc (c+d x) \left (\sqrt{\sec ^2(c+d x)}+1\right ) \sqrt{e \cot (c+d x)} \left (-3 \text{Hypergeometric2F1}\left (-\frac{1}{2},\frac{1}{4},\frac{5}{4},-\tan ^2(c+d x)\right )+3 \text{Hypergeometric2F1}\left (\frac{1}{4},\frac{1}{2},\frac{5}{4},-\tan ^2(c+d x)\right )+\cot ^2(c+d x) \text{Hypergeometric2F1}\left (\frac{3}{4},1,\frac{7}{4},-\cot ^2(c+d x)\right )+3\right )}{3 a d e^4} \]

Warning: Unable to verify antiderivative.

[In]

Integrate[1/((e*Cot[c + d*x])^(7/2)*(a + a*Sec[c + d*x])),x]

[Out]

(-4*Sqrt[e*Cot[c + d*x]]*Csc[c + d*x]*(3 - 3*Hypergeometric2F1[-1/2, 1/4, 5/4, -Tan[c + d*x]^2] + 3*Hypergeome
tric2F1[1/4, 1/2, 5/4, -Tan[c + d*x]^2] + Cot[c + d*x]^2*Hypergeometric2F1[3/4, 1, 7/4, -Cot[c + d*x]^2])*(1 +
Sqrt[Sec[c + d*x]^2])*Sin[(c + d*x)/2]^2)/(3*a*d*e^4)

________________________________________________________________________________________

Maple [C]  time = 0.28, size = 698, normalized size = 2.1 \begin{align*} \text{result too large to display} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(e*cot(d*x+c))^(7/2)/(a+a*sec(d*x+c)),x)

[Out]

1/6/a/d*2^(1/2)*(-1+cos(d*x+c))*(3*I*sin(d*x+c)*cos(d*x+c)*((-1+cos(d*x+c))/sin(d*x+c))^(1/2)*((-1+cos(d*x+c)+
sin(d*x+c))/sin(d*x+c))^(1/2)*((1-cos(d*x+c)+sin(d*x+c))/sin(d*x+c))^(1/2)*EllipticPi(((1-cos(d*x+c)+sin(d*x+c
))/sin(d*x+c))^(1/2),1/2+1/2*I,1/2*2^(1/2))-3*I*sin(d*x+c)*cos(d*x+c)*((-1+cos(d*x+c))/sin(d*x+c))^(1/2)*((-1+
cos(d*x+c)+sin(d*x+c))/sin(d*x+c))^(1/2)*((1-cos(d*x+c)+sin(d*x+c))/sin(d*x+c))^(1/2)*EllipticPi(((1-cos(d*x+c
)+sin(d*x+c))/sin(d*x+c))^(1/2),1/2-1/2*I,1/2*2^(1/2))-3*sin(d*x+c)*cos(d*x+c)*((-1+cos(d*x+c))/sin(d*x+c))^(1
/2)*((-1+cos(d*x+c)+sin(d*x+c))/sin(d*x+c))^(1/2)*((1-cos(d*x+c)+sin(d*x+c))/sin(d*x+c))^(1/2)*EllipticPi(((1-
cos(d*x+c)+sin(d*x+c))/sin(d*x+c))^(1/2),1/2+1/2*I,1/2*2^(1/2))+8*sin(d*x+c)*cos(d*x+c)*((-1+cos(d*x+c))/sin(d
*x+c))^(1/2)*((-1+cos(d*x+c)+sin(d*x+c))/sin(d*x+c))^(1/2)*((1-cos(d*x+c)+sin(d*x+c))/sin(d*x+c))^(1/2)*Ellipt
icF(((1-cos(d*x+c)+sin(d*x+c))/sin(d*x+c))^(1/2),1/2*2^(1/2))-3*sin(d*x+c)*cos(d*x+c)*((-1+cos(d*x+c))/sin(d*x
+c))^(1/2)*((-1+cos(d*x+c)+sin(d*x+c))/sin(d*x+c))^(1/2)*((1-cos(d*x+c)+sin(d*x+c))/sin(d*x+c))^(1/2)*Elliptic
Pi(((1-cos(d*x+c)+sin(d*x+c))/sin(d*x+c))^(1/2),1/2-1/2*I,1/2*2^(1/2))-6*cos(d*x+c)^2*2^(1/2)+8*cos(d*x+c)*2^(
1/2)-2*2^(1/2))*cos(d*x+c)^2*(cos(d*x+c)+1)^2/(e*cos(d*x+c)/sin(d*x+c))^(7/2)/sin(d*x+c)^7

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Maxima [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{\left (e \cot \left (d x + c\right )\right )^{\frac{7}{2}}{\left (a \sec \left (d x + c\right ) + a\right )}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(e*cot(d*x+c))^(7/2)/(a+a*sec(d*x+c)),x, algorithm="maxima")

[Out]

integrate(1/((e*cot(d*x + c))^(7/2)*(a*sec(d*x + c) + a)), x)

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Fricas [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(e*cot(d*x+c))^(7/2)/(a+a*sec(d*x+c)),x, algorithm="fricas")

[Out]

Timed out

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Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(e*cot(d*x+c))**(7/2)/(a+a*sec(d*x+c)),x)

[Out]

Timed out

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Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{\left (e \cot \left (d x + c\right )\right )^{\frac{7}{2}}{\left (a \sec \left (d x + c\right ) + a\right )}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(e*cot(d*x+c))^(7/2)/(a+a*sec(d*x+c)),x, algorithm="giac")

[Out]

integrate(1/((e*cot(d*x + c))^(7/2)*(a*sec(d*x + c) + a)), x)